[admin]

A-Level Maths Tuition Singapore/H2 Maths Tuition/JC Maths Tutor

Hi JC/A-Level Mathematics Tuition Students Singapore

Hi Wei Ren

N88/II/6

a) P(all the four cards are different) = (10x9x8x7)/(10x10x10x10) = 63/125

b) Since the first three are different. He has 10x9x8 choices. The fourth card is the same as either one of the first 3 cards, therefore he has 3 choices. Althogether he has 10x9x8x3 choices.

P(exactly 3 different pictures out of a total of four cards) = (10x9x8x3)/10^4 = 27/125

c) Required probability = 1 – P(all the four cards does not contain X or Y)= 1- (8/10)^4 = 0.591

d) P(n more cards are needed) (9/10)^n-1 x (1/10)
P( at most n more cards are needed) = 1/10 + (9/10)(1/10)………..(9/10)^n-1 x (1/10)

This is sum of GP

1- (9/10)^n > 099
n > 43.7

least value n = 44

From A level/H2 Maths Tutor

[admin]

A-Level Maths Tuition Singapore/H2 Maths Tuition/JC Maths Tutor

Hi JC/A-Level Mathematics Tuition Students Singapore

Good News!, there is a lesson on Thursday 5 April 4.30 pm to 6 pm on Function.

Come and join us. It is FOC

From A-Level Maths Tuition Singapore Tutor

[admin]

A-Level Chemistry Tuition Singapore/H2 Chemistry Tuition/JC Chemistry Tutor

Hi JC/A-Level Chemistry Tuition Students Singapore

Good News!, there is a lesson on Sunday 6 March 1 pm to 2.30 pm on Ksp

Come and join us. It is FOC

From A-Level Chemistry Tuition Singapore Tutor

[admin]

A-Level Economics Tuition Singapore/H2/H1/JC Economics Tuition

We are pleased to inform that J2 H1 Economics Tuition will start on 7 Apr Saturday at 7.30 pm to 9.30 pm by our dedicating and very experienced tutor Ryan Goh. He has coached many students to obtain distinction in A level examinations. Call 98639633 NOW!

From A-Level Tuition Singapore @ Kovan Admin

[admin]

A-Level Mathematics Tuition Centre Singapore/JC Maths/H2 Math Tuition and Tutor

Hi Genevieve, solutions are posted on Mathematics Resource

Please contact me if u have questions on the solutions

From A-Level Tuition Centre Singapore JC Maths Tuition Tutor

[admin]

A-Level Biology Tuition Singapore/H2/H1 Biology Tuition/JC Biology Tutor

Please be inform that J2 H2 Biology will atart on 31 March Saturday from 3.30pm to 5.30pm. Please call 98639633 to book a place.

From A-Level Biology Tuition Singapore – Admin

[admin]

A-level Physics Tuition Centre Singapore/JC Physics Tuition/H2 Physcis Tutor

Hi Ros

Will arrange a lesson to teach you.

From A-Level Physics Tuition Centre Singapore, JC Physics Tuition Tutor

[admin]

A-Level Mathematics Tuition Centre Singapore/JC Maths/H2 Math Tuition and Tutor

Please be inform that special lesson is arrange for JC2 H2 Math/Maths Tuition students who need extra help in Function and Differentiation on 5 Apr 4.30pm to 6pm. Lesson is FOC

From A-Level Tuition Centre Singapore JC Maths Tuition Tutor

[admin]

A-Level Mathematics Tuition Singapore/JC Maths/H2 Math Tuition and Tutor

Hi Micole

Solutions is in the Study Resources

All the Best

From A-Level Tuition Centre Singapore JC Maths Tuition Tutor

[admin]

A-Level Chemistry Tuition Singapore/H2 Chemistry Tuition/JC Chemistry Tutor

Hi JC/A-Level Chemistry Tuition Students Singapore

Good News!, there is a lesson on Sunday 25 March 8.30am to 10 am on Ionic Equilibrium.

Come and join us. It is FOC

From A-Level Chemistry Tuition Singapore Tutor

[admin]

A-Level Mathematics Tuition Singapore/JC Maths/H2 Math Tuition and Tutor

Hi Crystal as per request

Q2i)

let vector a = (1,2,1) and vector b = (2,4,c)

a.b = lallblCosx
2+6+c = root(6).root(20+c^2)Cos0
……………
Solve for c

4c)
Vector eqn r = (0,0,1)lamda
Cartesian eqn : x=0, y=0, Z=lamda

Q6) P=(0,0,0) line r=(3,1,4)+t(-2,1,2)

Let N be the foot of perpendicular from point P to the line
Since N lies on the line
ON = (3-2t,1+t,4+2t)
PN = ON – OP
= (3-2t,1+t,4+2t)

Since PN is perpendicular to the line
(3-2t,1+t,4+2t).(-2,1,2)=0
Solve for t and sub back to ON

Cheers!
From A-Level Maths Tuition Singapore Tutor

[admin]

A-Level Chemistry Tuition Singapore/H2 Chemistry Tuition/JC Chemistry Tutor

Hi A-Level/JC Chemistry Tuition Students – Singapore

For the same molecular formula, the cis isomer has a higher boiling point than the trans isomer.

Reasons:

_ The cis isomer is polar while the trans isomer is non-polar.

_ The polar cis isomer has permanent dipole- permanent dipole forces of
attraction between its molecules while the non-polar trans isomer has weak induced dipole-induced dipole forces of attraction between its molecules.

_ More energy is required to overcome the stronger permanent dipolepermanent dipole forces between the molecules of cis isomer.

_ Hence, the cis isomer has a higher boiling point than the trans isomer.

Why is the melting point of the cis isomers lower?

You might have thought that the same argument would lead to a higher melting point for cis isomers as well, but there is another important factor operating.

In order for the intermolecular forces to work well, the molecules must be able to pack together efficiently in the solid.

Trans isomers pack better than cis isomers. The “U” shape of the cis isomer doesn’t pack as well as the straighter shape of the trans isomer.
The poorer packing in the cis isomers means that the intermolecular forces aren’t as effective as they should be and so less energy is needed to melt the molecule – a lower melting point.

[admin]

A-Level Mathematics Tuition Singapore/JC Maths/H2 Math Tuition and Tutor

Hi Issac

Solution is in the study resource

All the best for your coming test

Cheers! – A-Level Maths Tuition Singapore – Tutor

[admin]

A-Level Mathematics Tuition Singapore/JC Maths/H2 Math Tuition and Tutor

Solutions posted on Mathematics Resources

From A-Level Maths Tuition Singapore Tutor

[admin]

A-Level Physics Tuition Singapore/H2 Physics Tuition/JC Physics Tutor

Hi Ki Hyun

Will print hard copy for u and the group.

From A-Level Physics Tuition Tutor Singapore

[Author]

Posts